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An aromatic hydrocarbon is a cyclic compound where all the atoms in the ring(s) are sp2 having a free "p" orbital to provide a pipeline or "conduit" in which Pi electrons can travel through being distributed throughout the molecule. This is referred to as a delocalized Pi electron system. A man by the name of Huckel came up with a mathematical rule which assumed a monocyclic planar ring system having 4n + 2 Pi electrons within the cyclic system where n = any integer beginning with the integer zero.
n 4n + 2 Pi electrons 0 4(0) + 2 = 2 1 4(1) + 2 = 6 2 4(2) + 2 = 10 3 4(3) + 2 = 14 4 4(4) + 2 = 18 etcThere are some cyclic hydrocarbons which have the proper number of Pi electrons according to the 4n + 2 Rule, but they are not aromatic. That is because at least one of the carbons within the ring is something other than sp2. For example, cycloheptatriene has six Pi electrons and seems to follow the 4n + 2 rule but one of the seven carbons is sp3 and therefore the ring is not planar. The ring must be planar in order for the Pi electrons to be delocalized in the ring. This gives the compound extra stability. Benzene is the most commonly known aromatic hydrocarbon having six Pi electrons with all six carbons sp2 and therefore the ring is planar ( a necessary condition). There are two conditions that must be present before a cyclic hydrocarbon can be aromatic:
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There are several classes of aromatic hydrocarbons.
The resonance stabilized conjugated structure of Benzene was first proposed by Kekule who, legend has it, had a dream vision of snakes chasing their tails around a circle. When he woke up he proposed the Benzene structure consisting of six carbons in a closed ring with alternating double and single bonds between its carbons. This makes all the carbons sp2 hybridized and the geometry around each carbon trigonal planar. Therefore, the benzene ring is flat or planar.
Kekule did, however, explain the resonance by suggesting two non-equivalent structures that were in equilibium with one another. There has never been any experimental evidence to suggest such an equilibrium mixture exists. A more modern picture based on the more modern molecular orbital approach to bonding and Resonance Theory suggests that there are two equivalent structures that are resonce hybrids of one another. The composite structure that would be closer to reality is a single molecule that has attributes of both resonance structures. All carbon-carbon bond lengths would be equal and lie between what a single bond between two carbons and a double bond between two carbons would be.
A brief biography of Friedrich August Kekulé
Examples of heterocyclic aromatics include :
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All aromatic hydrocarbons both benzenoid and non-benzenoid are resonance stabilized. They are water insoluble. They are also carcinogenic (cancer forming) if exposed with sufficient concentration and exposure time. They all undergo electrophilic aromatic substitutions. Most have a sweet aroma hence the reason for the name "aromatic".
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Benzene and its derivatives undergo substitution reactions where a hydrogen attached to a carbon atom in the ring is replaced by an electrophile. This can happen as many as six times on the Benzene ring. The general mechanism for such a substitution consists of a two step process plus the steps required to generate the electrophile. These steps depend upon the specific reaction involved.
There are several specific reactions involving electrophilic substitutions:
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In discussing electrophilic aromatic substitutions on Benzene, it was apparent that all six carbon atoms were equivalent in their ability to be the center of the substitution since the electron density exhibited by the Pi electron system was evenly distributed over the entire ring. When the electrophile decided to attach itself to one of the ring carbons with the help of a pair of Pi electrons from the ring, the electrophile was equally attracted to each carbon. If we should continue to substitute on a monosubstuted ring, the electrophiles are not equally attracted to the remaining five positions in the ring. It turns out that the group already attached to the ring will exert electronic influence on the remaining five positions affecting the kinetics and directing the next electrophile to positions that are more attractive than other positions in the same ring. This kinetic and directive effects differ for different groups.
There are some groups which when attached to one of the ring carbons of Benzene or some other Benzenoid will activate the ring toward further substitution. They do this by increasing the negative electron density in the ring thus making the ring more attractive to the approaching electron seeking electrophile. There are two ways in which the electron density can be affected:
Notice that each of the strong activators have a lone pair attached to the atom bonded to a ring carbon. Through resonance this lone pair increases the electron density making the ring more active.
All activators, strong, moderate, or weak will direct the electrophile to the ortho or para positions relative to the first substituent. To understand why the ortho and para positions are the most attractive to the electrophile you have to see where the negative electron density accumulates within the ring when a group activates the ring. Let's take an example with the -NH2 group.(Fig 6) You can see that through the writing of resonance structures the extra negative electron density coming into the ring accumulates at the two ortho and one para positions. Therefore, when an electron seeking electrophile forms a sigma complex it does so more likely at the ortho and para positions. This is true about all activator groups. They will all direct Ortho and para.
The distribution from a probalistic view is that we should expect twice as much ortho disubstituted product as para since there are twice as many ortho positions. So the O/P ratio should be 2/1 or 67% Ortho and 33% para. One thing that will alter this distribution is the steric factor. If either of the substituents are bulky this will discourage the attachment at the Ortho position and will increase the amount of para disubstituted product. This can be very dramatic if one of the substituents is a tertiary butyl group. The dramatic results in the Nitration of tertiary butyl benzene is virtually 100% para because of the bulky nature of the tertiary butyl and the nitro groups. They would get in each others way being attached to adjacent carbons.
An interesting situation arises with the weakly deactivating groups which include the halogens (Fig 5). The halogen atoms because of their extreme electronegativity will pull electrons out of the ring leaving the ring more positive ,and therefore, less attractive to the incoming electrophile. Such rings are said to be deactivated toward electrophilic substitution. However, the three lone pairs of non-bonding electrons found on the halogen atom will provide increased electron density at the ortho and para positions. To understand this you have to think of a ring that is deactivated ,but a ring which the relative electron density is greater at the ortho and para positions due to the resonance effect of the lone pairs. So if the substitution occurs it will be sluggish but occur either at the ortho or para positions.
The other two deactivator groupings (Fig 5) are said to be meta directors. Most of these groups either have atoms attached to a ring carbon with a Pi bond or highly electronegative atoms attached as in the case of -CF3 and -CCl3 groups which are strong deactivators (Fig 5). These deactivators reduce the negative electron density of the ring by sucking it out of the ring either by resonance (Those atoms directly attached to the ring that have at least one Pi bond) or inductive effect as in the case of the -CCl3, CF3, and -NR3+ groups. All deactivators with the exception of the weakly deactivating groups spoken of earlier will be meta directors. This is because when the electron density is dimenished in the ring , it occurs more at the ortho and para positions leaving the meta position relatively more negative.(Fig 7)Therefore, if the electrophile does manage to be attracted to the deactivated ring, it will find the meta position that will be more negative and more attractive to the incoming electrophile.
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Alkyl Benzenes will undergo free radical substitution on the alkyl portion of an Alkyl Benzene. For example, Ethyl Benzene will undergo Free Radical Bromination to form 1-Bromo-1-Phenylethane (Fig 8)
The first step initiates the reaction by generating halogen free radicals using enough thermal or radiant energy to break the covalent bond between the two halogen atoms. Steps 2 and 3 are propagation steps. Propagation steps are steps that each produce an essential intermediate for the other step so, in essence, they "feed" each other and propagate the reaction. This is common in all Free Radical reactions. The question might arise as to why the hydrogen atom on the carbon directly attached to the benzene ring is particularly easy to abstract. The answer to that question lies in the stability of the carbon free radical (step 2 in Fig 8). This free radical is what is called a benzylic free radical. Benzylic free radicals are particulary stable even moreso than tertiary free radical carbons. This is because of the ability of the unpaired electron to be spread out over the ortho and para positions of the ring thereby stabilizing the free radical carbon. (Fig 9)
This spreading out of the electron charge density of the unpaired electron onto four carbons(benzylic carbon, two ortho and one para carbons) stabilizes the free radical better than even a tertiary radical.
R. H. Logan, Instructor of Chemistry, Dallas County Community College District, North Lake College.
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All textual content copyrighted (c) 1997 R.H. Logan, Instructor of Chemistry, DCCCD All Rights reserved
Revised: 7/12/97
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